Math, asked by indranil8143, 1 month ago

If f(x) = x2

-117 = 0 then the iterative formula for Newton Raphson Method is given

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Answers

Answered by anirudhabandyo12
0

Answer:

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Step-by-step explanation:

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Answered by steffiaspinno
0

If f(x) = x2-117 = 0 then the iterative formula for Newton Raphson Method is given by  x(n+1)=0.5[x(n)+\frac{117}{x(n)}]\\\\.

Step-by-step explanation:

Given,

f(x) = x^{2} - 117 = 0

To be found,

Iterative formula for Newton Raphson method = ?

Concept to be used - Iterative formula for Newtons Raphson method depends on initial values and also converges slowly.

Taking,

x(n+1) = 0.5[x(n) + \frac{117}{x(n)}]

Since, N = 117,

Therefore,

x(n+1)=0.5[x(n)+\frac{117}{x(n)}]\\\\

Hence, the iterative formula for Newton Raphson Method is given by x(n+1)=0.5[x(n)+\frac{117}{x(n)}]\\\\

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