If f(x) = x2/3 be a real
valued function on the
interval(-8,8]such that
it is not differentiable in closed interval (-8,8)
and not continuous in open interval (-8,8)
it is not differentiable in closed interval (-8.8]
but continuous in open interval (-8, 8)
|-8.8) and
it is differentiable in closed interval
continuous in open interval (-8, 8)
it is not differentiable in open interval (-8,8) but
it is continuous in closed interval (-8.8)
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Yaar it is so hard
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