Question

If f(x) = (x² +3 x≤2)(5x+7, x>2) , then find
f(a) f(3) b)f(2) c) f(O) ​

Answer 1

Step-by-step explanation:

F(x) =x²+3 , x<=2

F(x)=5x+7 , x>2

So to find f(a), f(3),f(2),f(0)

Put a, 2,3,0 in place of X according to the situation

So, F(3) verify the situation 2nd

So f(3)=5(3)+7

=15+7

=22

Again f(2)is m verify situation 1st

So f(2)=2²+3

=4+7=7

Similarly f(0) verify the situation 1st

So f(0)=o²+3

=0+3= 3

Answer 2

Answer:

(a) f(x) = x2 + 3,      x ≤ 2

= 5x + 7,            x > 2

We have to find f(3) we'll go with 2nd one cz x can be greater than 2

f(x)=5x+7

f(3) = 5(3) + 7 = 15 + 7 = 22

(b) f(x) = x2 + 3,      x ≤ 2

We have to find f(2) we'll go with 1st one cz x can be less or equal to 2

f(x)= $x^{2}$+3

f(2) = (2)²+3 = 4+7 = 7

(c) f(x) = x2 + 3,    x ≤ 2

We have to find f(0) we'll go with 1st one cz x can be less or equal to 2

f(x)=$x^{2}$+3

f(x)= $0^{2}$+3

f(0) = $0^{2}$+ 3

= 3