If f(x)=x2-3x+10 Find f'(50) and f'(11)
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Answer:
-40 and 0 respectively
Step-by-step explanation:
50×2-3×50+10=100-150+10=-40
that's for f'(50) where x=50
11×2-3×11+10=22-33+10=-10+10=0
that's for f'(11) where x=11..
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