If f(x)= x² – 3x+10. Find f'(50) and f'(11)
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Answer:
f(x)=x^2-3x+10
Step-by-step explanation:
f(50):
substitute x^2-3x+10 with f(50)
f(50)=50^2-3(50)+10
=2500-150+10
=2500-160
=2340
f(11):
substute x^2-3x+10 with f(11)
f(11)=11^2- 3(11) +10
=121-33+10
=121-43
=78
hope it's helpful
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