Question

if f(x)=x2-4x+3,then find the values of f(1),f(-1),f(2),f(3) also find the zeros of the polynomial f(x)

Answer 1

Answer:

0,8,-1,0

Step-by-step explanation:

f(x) =

${x}^{2} - 4x + 3$

f(1) =

${1 }^{2} - 4(1) + 3 \\ = 1 - 4 + 3 \\ 4 - 4 = 0$

f(-1)=

${ - 1}^{2} - 4( - 1) + 3 \\ = 1 + 4 + 3 = 8$

f(2)=

${2 }^{2} - 4(2) + 3 \\ = 4 - 8 + 3 \\ = 7 - 8 = - 1$

f(3)=

${3}^{2} - 4(3) + 3 \\ = 9 - 12 + 3 \\ = 12 - 12 \\ = 0$

Answer 2

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