If f(x)=x² +5x+7 then which of the following is / are correct
(A) f(x)<0 VXER
(B) f(x)>1 x€ (-0, -3) (-2,00)
(C) f(x)>3 Vxe (-0, 4)(-1,00)
(D) f(x) > 0 VXER
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Answer:
c) f(x)>3 Vxe (-0, 4)(-1,00)
Step-by-step explanation:
f(x)=x²-5x+7
f(2)=2²-5.2+7=4-10+7=11-10=1
f(-1)=(-1)²-5.(-1)+7=1+5+7=13
f(1/3)=(1/3)²-5(1/3)+7=1/9-5/3+7=49/9
∴, f(2)-f(-1)+f(1/3)
=1-13+49/9
=58/9-13
=-59/9
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