Question

If f(x) = x2-9/x+5, find f(o), f(-1), f(1/k)​

Answer 1

Answer:

$f(0) = 0^2 - 9(0) + 5 = 0 - 0 + 5 = 5$

$f(-1) = (-1)^2 - 9(-1) + 5 = 1 - (-9) + 5 = 1+9+5 = 15$

$f(\frac{1}{k}) = (\frac{1}{k})^2 - 9(\frac{1}{k}) + 5 = \frac{1}{k^2} - \frac{9}{k} + 5$

Hope it helps!