Question

If f(x) = x2 – x + 1; g(x) = 7x – 3, be two real functions then (f + g)(3) is

Answer 1

Answer:

if (f+g)(3) then

(x2-x+1-7x-3)(3)

=x2-x-7x+1-3)(3)

=x2-8x-2)(3)

=3x2-24x-6

Answer 2

Answer:

$(f+g)(3)=-11.$

Step-by-step explanation:

Given,

$f(x)=x^2-x+1; g(x)=7x-3.$

Let,

$f(3)=(3)^2-(3)+1=9-3+1=7.$

$g(3)=7(3)-3=21-3=18.$

$(f+g)(3)=f(3)+g(3)$

                $=7-18=-11$