Question

if f(x) =x3-3x+2x+5 find f(-1), f(-2),f(1)

Answer 1

Answer:

f(-1)=5

f(-2)=1

f(1)=5

Answer 2

Answer:

$f(x) = {x}^{3} - 3x + 2x + 5 \\ f( - 1) = ( - 1)^{3} - 3( - 1) + 2( - 1) + 5 \\ f( - 1)= - 1 + 3 - 2 + 5\\ f( - 1)=5 \\ \\ \\ f( - 2) = ( - 2) ^{3} - 3( - 2) + 2( - 2) + 5 \\ f( - 2) = - 8 + 6 - 4 + 5\\ f( - 2) = - 1 \\ \\ \\ f( 1) = ( 1)^{3} - 3( 1) + 2( 1) + 5 \\ f( 1)= 1 - 3 + 2 + 5\\ f( 1)=5$