If f(x) = x3 − 3x + sin x + x . cos x, then f(x) + f(−x) = ________
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Given :
f(x) = x³ − 3x + sin x + x . cos x
To Find : f(x) + f(−x)
Solution:
f(x) = x³ − 3x + sin x + x . cos x
f(-x) = (-x)³ − 3(-x) + sin(- x) +(- x) . cos (-x )
Cube of -1 is - 1
Sin(-x) = - Sinx
Cos(-x) = Cosx
=>f(-x) = -x³ + 3x - sin x - x . cos x
=> f(-x) = - ( x³ − 3x + sin x + x . cos x )
=> f(-x) = - f(x)
=> f(x) + f(-x) = 0
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