Question

if f(x) x4-2x2+7x+4 and p(x) x2-3 divide both​

Answer 1

Answer:

x^4-2x^2+7x+4÷x^2-3

x^2-3=0

x^2=3

x=√3

f(x)=x^4-2x^2+7x+4

f(√3)=(√3)^4-2(√3)^2+7(√3)+4

9-2(3)+7(√3)+4

9-6+7√3+4

7+7√3

Remainder is 7+7√3

Step-by-step explanation:

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