if f(x)=x⁴-2x³+3x²-9x+b is a polynomial such that when it is divided by x+1 and x+1 , the remainder when f(x) is divided by x-2
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When f(x) is divided by x-1 and x+1 the remainder are 5 and 19 respectively.
∴f(1)=5 and f(−1)=19
⇒(1)4−2×(1)3+3×(1)2−a×1+b=5
and (−1)4−2×(−1)3+3×(−1)2−a×(−1)+b=19
⇒1−2+3−a+b=5
and 1+2+3+a+b=19
⇒2−a+b=5 and 6+a+b=19
⇒−a+b=3 and a+b=13
Adding these two equations, we get
(−a+b)+(a+b)=3+13
⇒2b=16⇒b=8
Putting b=8 and −a+b=3, we get
−a+8=3⇒a=−5⇒a=5
Putting the values of a and b in
f(x)=x4−2x3+3x2−5x+8
The remainder when f(x) is divided by (x-2) is equal to f(2).
So, Remainder =f(2<
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