If f(x) =x⁴-2x³+3x²-ax+b is dimension divided by (x-1) and (x+1) it leave the remainder 5 and 19 respectively find a and b
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Step-by-step explanation:
f(1) is 1-2+3-a+b=0
-a+b= -2
f(-1)=1+2+3+a+b=0
=a+b=. -6
a = -b -6
now b+6+b =-2
2b= -8
b= -4
a= -2
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