If f(x)=x⁴+3x²-ax+b is a polynomial such that it is divided b²y x-1 and x+1 remander are 5 and 19.Find remainder when f(x) is divided my x-2
Answers
Answer:
There is theorem known as “Polynomial Remainder Theorem” or “ Bezout’s Theorem”. It is Stated as -
A Polynomial f(x) if divided by a linear polynomial (x-a) leaves remainder which equals f(a).
So , getting back to our question -
f(x) = x^4 - 2x^3 + 3x^2 - ax + b
So , when it is divided by (x - 1) it’ll leave a remainder = f(1) = 5 (Given).
f(1) = 1^4 - 2×1^3 + 3×1^2 - a×1 + b = 5
=> 1 - 2 + 3 - a + b = 5
=> a - b = (-3) …. Eqn(1)
Now , Similarly -
f(-1) = (-1)^4 - 2×(-1)^3 + 3×(-1)^2 - a×(-1) + b = 19
=> 1 + 2 + 3 + a + b = 19
=> a + b = 13 …. Eqn(2)
Now , adding equations (1) and (2) , We’ll get -
(a+b) + (a-b) = (-3) + 13
=> 2a = 10 => a = 5
So , (a +b) = 13 implies b = 8
Hence , Values of a and b are 5 and 8 respectively.
Answer:
hope it helps good afternoon happy independence day.