if f(x)=x4+ax3+bx2+cx+d is a polynomial such that f(1)=10,f(2)=20,f(3)=30,find the value of f(12)+f(-8)/10=?
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Answer:
f(12)=120
f(-8)=-80
f(12)+f(-8)/10=120+(-80)/10
120-8
112
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