If f(x) = x50 is divided by x2 − 3x + 2 then find the sum of coefficient of x and constant term in the remainder
Answers
Given :- If f(x) = x^50 is divided by x² – 3x + 2. then find the sum of coefficient of x and constant term in the remainder.
Solution :-
given that, f(x) is divided by x² - 3x + 2 , which can be written as ,
→ x² - 3x + 2
→ x² - 2x - x + 2
→ x(x - 2) - 1(x - 2)
→ (x - 1)(x - 2)
now, according to remainder theorem , when a polynomial p(x) is divided by (x - a) , remainder will be f(a) .
so, when p(x) is divided by (x - 1) , we get,
→ p(x) = x^50
→ p(1) = (1)^50
→ p(1) = 1
and, when p(x) is divided by (x - 2) , we get,
→ p(x) = x^50
→ p(2) = (2)^50
then,
→ p(x) / (x - 1)(x - 2)
→ {p(x) / (x - 1)} * {p(x) / (x - 2)}
→ (1 * 2^50) remainder
→ 2^50 remainder .
therefore,
→ sum of coefficient of x in remainder = 0 .
and,
→ constant term in the remainder = 2^50 .
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