*If f(x) = xsinx, then the value of f'(0) will be _____.*
1️⃣ 0
2️⃣ -1
3️⃣ 1
4️⃣ Not defined
Answers
Answered by
0
Answer:
f(x)=xsinx
f'(x)=(x).(cosx)+1.(sinx)
f'(0)=0.cosx+1.sin0
f'(0)=0
option 1
Answered by
0
Answer:
Answer is 0.
Step-by-step explanation:
f(x) = xsinx
=> f'(x) = xcosx + sinx
=> f'(0) = 0×cos0 + sin 0
=> f'(0) = 0×1 + 0
=> f'(0) = 0
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