Question

if f(x)=xsinx then the value of f'(0) will be​

Answer 1

Answer:

0

Step-by-step explanation:

f(X)=xsinx

f(0)=0×sinx

f(0)= 0

Answer 2

If f(x) = xsinx then the value of f'(0) will be 0

Given : f(x) = xsinx

To find : f'(0)

Solution :

Step 1 of 3 :

Write down the given function

The given function is

f(x) = xsinx

Step 2 of 3 :

Differentiate both sides with respect to x

Differentiating both sides with respect to x we get

$\sf f'(x) = sinx + xcosx$

Step 3 of 3 :

Put x = 0 in f'(x)

Putting x = 0 in f'(x) we get

$\sf f'(0) = sin0+ 0.cos0$

$\sf \implies \: f'(0) = 0+ (0 \times 1)$

$\sf \implies \: f'(0) = 0+0$

$\sf \implies \: f'(0) = 0$

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