If f(x+y)=f(x)f(y) and f(5)=32, then f(7)=
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Step-by-step explanation:
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f(x+y)=f(x).f(y)
Put x=1,y=1
f(x+y)=f(x).f(y)
⇒f(2)=f(1)f(1)
⇒f(3)=f(2)f(1)=f(1)
3
⇒f(4)=f(3)f(1)=f(1)
4
⇒f(5)=f(4)f(1)=f(1)
5
Givenf(5)=32
∴f(1)=2
And f(2)=4
Now,
f(7)=f(5)f(2)=32×4=128
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