If f(x + y) = f(x) < f(y) V x, y e R. Find possible value of f(0) if f(0) > 0 X
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Answer:
f(xy)=f(x).f(y)
f(0)=1 as f(0)
=0
⇒f(x)=1
dx
dy
=f(x)=1
⇒y=x+c
At, x=0,y=1⇒c=1
y=x+1
⇒y(
4
1
)+y(
4
3
)=
4
1
+1+
4
3
+1=3
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