Math, asked by nishanthisandhiya242, 2 days ago

If f(x,y)=sinxyf(x,y)=sin⁡xy, then the value of the second degree first term in Taylor’s series at (1,−π2)(1,−π2) is

Select one:

a. π28(x−1)2π28(x−1)2

b. −π24(x−1)2−π24(x−1)2

c. π24(x−1)2π24(x−1)2

d. −π28(x−1)2



Answers

Answered by rahulkr049484847
0

Answer:

option d is correct answr

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