Question

If f( xcube -6x^2+11x +8)= x+2 find the sum of possible value of f(14)​

Answer 1

Answer:

1746

Step-by-step explanation:

Given,

${f(x) = {x}^{3} - {6x}^{2} + 11x + 8 = x + 2}$

Substituting f(14)

${f(14) = {(14)}^{3} - 6 {(14)}^{2} + 11(14) + 8 = 14 + 2}$

$= > 2744 - 1176 + 154 + 8 = 16$

$= > 2906 - 1176 - 16$

$= > 2906 - 1160$

$= > 1746$

Answer 2

Answer:

X3-6 x +11 x -6=0

put x=1 1-6+11=0 1 is root equation ,so (x-1) is factor of x3-6x2 +11 x-6, x2-5 x+6=0 ( x-3) ( x-2) =0 x=2,3