if f(y) = y4 - 2y3 + 3y2 -ay - b , when we divided by y-1 , gives the remainder 6, then find the value of a+b
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f(1)=(1)4-2(1)3+3(1)2-a(1)-b
6=1-2+3-a-b
6=2-(a+b)
6-2=-(a+b)
4/-1 =a+b
a+b=-4
6=1-2+3-a-b
6=2-(a+b)
6-2=-(a+b)
4/-1 =a+b
a+b=-4
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