Question

if f(z) = z^2 - 3√2- 1, then find of (3√2)

Answer 1

Hey There!!

Here we have


$f(z)=z^2-3\sqrt{2}z-1$

We can find the value as follows:
$f(3\sqrt{2}) = (3\sqrt{2})^2 - 3\sqrt{2} \times (3\sqrt{2}) - 1 \\ \\ \\ \implies f(3\sqrt{2}) = \bcancel{(3\sqrt{2})^2}-\bcancel{(3\sqrt{2})^2} - 1 \\ \\ \\ \implies \boxed{f(3\sqrt{2})=-1}$


Hope it helps
Purva
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