if fair coin is tossed 10 times find the probability that it shows head
5 times
in the first four tosses and tail in last six tosses
Answers
Answered by
5
Step-by-step explanation:
The probability of x successes in n trials is:
P(x) = nCx * p^x * q^(n-x)
where
n = number of trials = 10
x = number of successes(head) among n trials = 5
p = probability of success(head) in any one trial = 1/2
q = probability of failure in any one trial (q = 1 - p) = 1/2
P(x) = 10C5∗(1/2)5∗(1/2)5=252∗(1/2)10≈0.246
Therefore, P(x) ≈ 0.246
Answered by
16
Answer:
Step-by-step explanation:
The probability of x successes in n trials is:
P(x) = nCx * p^x * q^(n-x)
where
n = number of trials = 10
x = number of successes(head) among n trials = 5
p = probability of success(head) in any one trial = 1/2
q = probability of failure in any one trial (q = 1 - p) = 1/2
P(x) = 10C5∗(1/2)5∗(1/2)5=252∗(1/2)10≈0.246
Therefore, P(x) ≈ 0.246
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