Question

If fare of a taxi for 1st kilometer in Rs.15 and for after 1 kilometer is Rs18 then find the fare for 12 kilometer

Answer 1

Answer:

The taxi fare for first km=15The taxi fare for 2nd km=15+8=23The taxi fare for 3rd km=15+8+8=31 and so on,Therefore, the taxi fare form the sequence 15,23,31,...Clearly, it is an AP with first term a=15 and common difference d=8Therefore, answer is 0.

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