if father is colorblind and mother is a carrier a) write the genotype of both the parents. b) what will be the phenotype expression of the offspring
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Colour blindness is an X-linked recessive disorder. In the above question, Mother is a carrier . Therefore, her genotype must be X^C X. The father is normal, hence his genotype must be XY. By using punnet square, the possible genotypes and phenotypes in next generation will be:
X Y
X^C X^C X X^C Y
X XX XY
The possible genotypes are- X^C X, X^C Y, XX and XY. The four possible phenotypes are- Carrier Daughter (X^C X), Affected son (X^C Y), Normal daughter (XX), Normal son (XY).
Explanation:
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