If father is twice as old as his son and also 32 years older than his son. What is the age of father?
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ANSWER:
Given:
- Father is twice as old as his son.
- He is 32 years older than his son.
To Find:
- Age of father
Solution:
Let us assume that age of father is x years.
So, as we are given that, the father is twice as old as his son, hence,
⇒ Age of Father = 2 × Age of Son.
⇒ x = 2 × Age of Son.
Hence,
⇒ Age of Son = x/2 years.
We are also given that,
⇒ Father is 32 years older than son.
So,
⇒ Age of Father = 32 + Age of Son
⇒ x = 32 + x/2
Transposing x/2 to LHS,
⇒ x - x/2 = 32
Taking LCM,
⇒ (2x - x)/2 = 32
⇒ x/2 = 32
Transposing 2 to RHS,
⇒ x = 32 × 2
Hence,
⇒ x = 64.
Therefore, age of father is 64 years.
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