if father is twice as old as his son the sum of their ages is 99 years find their ages
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Answered by
14
Let the son’s age=x
Father’s age = 2x
By question,
x+2x=99
3x=99
x=99/3
x=33
Father’s age=2x=2 x 33= 66
Son’s age=x =33
Father’s age = 2x
By question,
x+2x=99
3x=99
x=99/3
x=33
Father’s age=2x=2 x 33= 66
Son’s age=x =33
Answered by
2
Answer:
Age of his son=x
Age of his father is twice of his son age =2x
Therefore 2x+x=99
3x=99
x=99/3
x=33
His son age=33 years
His father age=2x
=2*33
=66 years
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