If father is twice as old as old as his son and also 32 years older than his son . what is the age of father
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Answer:
the son age will be 32 mark and the fathers 64
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age of son = x
age of dad = 2x+32
Solving...
2x=-32
x= -32/2 = 16
Age of son(x) = 16 yrs
Father age = 16*2+32= 64 yrs
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