if father is twice old as his son and also 29 years older than his son.what is the age of the father?
Answers
The age of the father is 58 years.
To find:
Age of father = ?
Solution:
Given: Father is twice old as his son and also 29 years older than his son.
Let us assume that son's age be x. It is given that Father's age is twice old as his son. Considering the age of father's age as x, son's age will be 2x.
It is also given that father is 29 years older than his son. Hence, the equation becomes
2x - x = 29
x = 29
Thus, age of the son is 29 years.
Age of father = 2x = 2(29) = 58 years.
Answer:
The age of the father is 58 years.
To find:
Age of father = ?
Solution:
Given: Father is twice old as his son and also 29 years older than his son.
Let us assume that son's age be x. It is given that Father's age is twice old as his son. Considering the age of father's age as x, son's age will be 2x.
It is also given that father is 29 years older than his son. Hence, the equation becomes
2x - x = 29
x = 29
Thus, age of the son is 29 years.
Age of father = 2x = 2(29) = 58 years.
hope it is helpful