Question

If [Fe³+]=0.001mol.L-1, [ I- ]=0.001 mol.L−1, [Fe²+]=1 mol.L-1, what is spontaneous direction for the reaction
2Fe³+ + 2I- = 2Fe2+ + I2 ( φ⦵(Fe^ 3+ /Fe^ 2+ )=0.771V, φ⦵(I 2 /l^ - )=0.5355V)

A.Forward direction

B.Backward direction

C.In equilibrium

D.Can NOT be determined

[ For clear understanding picture is attached ]

* Incorrect response will be reported *
Thank you.
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Answer 1

Answer:

B.

Explanation:

For the given reaction E° of the cell =0.77-0.5355= 0. 2345v

EMF of cell = E° - 0.059/2log[Fe^2+]^2/[Fe3+]^2*[I^-]^2

= 0.2345 - 0.0295log 1/(.001)^2(.001)^2

=0.2345- 12*0.0295

= -0.1195v

negative cell emf so backward direction is spontaneous