Question

If [Fe³+]=0.001mol.L-1, [ I- ]=0.001 mol.L−1, [Fe²+]=1 mol.L-1, what is spontaneous direction for the reaction
2Fe³+ + 2I- = 2Fe2+ + I2 ( φ⦵(Fe^ 3+ /Fe^ 2+ )=0.771V, φ⦵(I 2 /l^ - )=0.5355V)

A.Forward direction

B.Backward direction

C.In equilibrium

D.Can NOT be determined

[ For clear understanding picture is attached ]

* Incorrect response will be reported *
Thank you.​

Answer 1

Answer:

We know,

ΔG

o

=−nFE

cell

o

Since 2 electrons are involved so n=2.

ΔG=−nFE

cell

o

=−2×96000×2=−384000 J=−384 kJ