If fi R-R is a
function defined by
(a) = 2x+1 then prove
f is bijection
ove that
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Solution :
Given function :
f : R → R , f(x) = 2x + 1
• Whether f(x) is one-one :-
Let f(x1) = f(x2)
=> 2x1 + 1 = 2x2 + 1
=> 2x1 = 2x2
=> x1 = x2
Since f(x1) = f(x2) => x1 = x2 , hence f(x) is one-one function .
• Whether f(x) is onto :-
Let y = f(x)
=> y = 2x + 1
=> 2x = y - 1
=> x = (y - 1)/2
Since the domain of the function is R , thus for x to be real y can be any real number .
=> Range (f) = R
=> Range (f) = Co-domain (f)
Since the range and the Co-domain of the given function are equal , hence f(x) is onto function .
Since the given function f(x) is one-one and as well as onto , thus f(x) is bijective .
Hence proved .
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