Question

if fifth and sixth terms are 100 then find 100th and 101th terms in an arthematic progression

Answer 1

ATQ,

a5=100 a6=100

i.e,a+4d=100 -----(1)

a+5d=100------(2)

on solving (1) and (2) we get

d=0------(3)

using (3) in (1) we get

a=100------(4)

a100=a+99d

(from 3 and 4 we get)

a100=100

similarly,

a101=100