If fig., ABCD is a parallelograme with B=100
and DAC=50
then what is the value
of x
Answers
Answered by
3
Answer:
Given that,
∠BED=90
0
, Then ∠AEC=45
0
∠EAC+∠EAB=90
0
∴BAEC is a rectangle.
Then,
∠EAC=EAB=45
0
and ABC=45
0
Given that, ∠ADE=50
0
In ΔACD,
∠ACD+∠ADC+∠DAC=180
0
90
0
+50
0
+∠DAC=180
0
∠DAC=180
0
−140
0
∠DAC=40
0
Then,
∠EAC+∠ABC−2∠DAC
=45
0
+45
0
−2×40
0
=90
0
−80
0
=10
0
Hence, this is the answer.
Answered by
0
Answer:
Please send the Pic of th given figure
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