Question

if fig X and y arc mid points of AB and AC respectively <ABC = 60° xy = 2.8cm.​

Answer 1

Given: X and Y are mid points of AB and AC respectively.

In △ABC, using mid point theorem

XY∥BC and XY= 2/1 BC

Thus, XY=3 cm

Since, D is mid point of AB , BX = 2/1AB= 2/1 (5.4)=2.7 cm

Also, E is mid point of AC, CY= 2/1 AC= 2/1 (5)=2.5 cm

Now, Perimeter of XYCB = XY+YC+BC+XB

Perimeter of XYCB = 3+2.5+6+2.7

Perimeter of XYCB = 3+2.5+6+2.7

= 14.2 cm