if figure 6.28,find the value of X and Y and then show that AB || CD
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AB || CD and EF is transversal (assume the transversal as EF) therefore
x=130° (corresponding angles)
Again,
AB || CD and EF transversal
x=y (alternate angles)
y=130°
x=130° (corresponding angles)
Again,
AB || CD and EF transversal
x=y (alternate angles)
y=130°
tanushree20:
thanks sie
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