Math, asked by tsc4646, 2 months ago

if figure AB=AC and D is mid point of BC. prove that triangle ADB=triangle ADC.

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Answered by Anonymous

Answer:

$\huge \underbrace \pink{★ Answer❀✿°᭄★}$

$given \: \\AB=AC \\ BD=DC→(i)in \: ΔABD \: and\: ΔACD \\ AB=AC \: (given) \\ </p><p>BD=DC \: from \: eq \: (i) \\ AD=AD \: common \: from \: sss \: rule$

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if figure AB=AC and D is mid point of BC. prove that triangle ADB=triangle ADC.​

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if figure AB=AC and D is mid point of BC. prove that triangle ADB=triangle ADC.