Question

If figure AB || CD and CD| EF, find angle ACE.​

Answer 1

Answer:

<ACE=20°

Given:

AB||CD and CD||EF

To find:

<ACE

Solution:-

EF||CD (Given)

So

<E+<ECD=180°. {Sum of co.Int.<s}

130°+<ECD=180°

<ECD=180°-130°

<ECD=50°

Now; AB||CD

<A=<ACD {A.I.A}

70°=<ACD

Therefore

<ACD=70° and <ECD=50°

So;

<ACE=<ACD-<ECD

<ACE=70°-50°

<ACE=20°

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<ACE=20°

Answer 2

$\sf{Hello,Brainly\:User}$

According to the given question

We have to find angle ACE.

Hence,

$⟹\sf(EF||CD ) = > parallel</p><p></p><p>$

$⟹\sf(< E+ < ECD=180°)$

$⟹\sf(130 °+ < ECD=180 °) \\ </p><p>⟹\sf( < ECD=180 ° -130 ° )$

$⟹\sf( < ECD=50°)$

$⟹\sf(AB||CD) \\ </p><p>⟹\sf( < A= < ACD )$

$⟹(70°= < ACD)$

So,

$⟹\sf( < ACD=70°) \\ ⟹ \sf (< ECD=50°)$

Hence,

$⟹\sf(< ACE= < ACD- < ECD)$

$⟹\sf( < ACE=70°-50°) \\ </p><p>⟹\sf( < ACE=20°)$

Therefore answer = <ACE=20°

Note that

( ° ) => This symbol means degree.