Question

if figure ABC is an equilateral triangle and D is a point on AC prove that it is greater than BD​

Answer 1

Step-by-step explanation:

Consider the triangle ,triangle ADB

angle BAD = 60 ,angle ABD < \angle ABC \implies \angle ABD < 60

Now, in a triangle, side opposite larger angle is greater than the side opposite smaller angle.

Hence, as BD is opposite angle BAD,,AD is opposite angle ABD and we saw that angle ABD < \angle BAD = 60

therefore BD > AD