If Find dy /dx i ) y = (x+1) (x²+3)?
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Step-by-step explanation:
x ( x2 + 3 ) +1 ( x2 + 3 )
x^3 + 3x + x^2 + 3
x^3 + x^2 + 3x + 3
I.e y = x^3 + x^2 + 3x + 3
now , differentiating each term w.r.t x
dy/dx = 3x^2 + 2x + 3 + 0
= 3x ^2 + 2x + 3
Hope it help you
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