If , find the value of x=7-4√3 then what is x³+1/x³
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Answer:
hey here is your answer ✌
2702
Step-by-step explanation:
X= 7–4√3
X^3 =( 7–4√3)^3
Formula (a-b)^3 = a^3-3a^2b+3ab^2-b^3
= (7)^3 - 3(7)^2*4√3+3*7*(4√3)^2 - (4√3)^3
= 343–3*49*4√3+3*7*4√3*4√3- 64*3√3
= 343–588√3+1008- 192√3
=343+1008–588√3–192√3
=1351–780√3
1351–780√3
1/x = 1/(7–4√3)
7+4√3÷(7–4√3)(7+4√3) Rationalising the denominator
7+4√3/49–48= 7+4√3/1 = 7+4√3
1/X^3 =(7+4√3)^3
(a+b)^3=a^3 +3a^2b +3ab^2+b^3
(7+4√3)^3= 343+588√3+1008+192√3
= 343+1008+588√3+192√3
= 1351+780√3
1351+780√3
Adding 1351–780√3+1351+780√3
= 1351+1351 = 2702
hope it helps you ✌✌✌✌
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