If first 20 prime numbers are arranged in descending order..which of the number will occur in 8th position from left end of the row?
Answers
The number that is at 8th position from left end of the row is 41.
Step-by-step explanation:
Prime numbers are numbers that have exactly two factors: 1 and itself.
First twenty prime numbers are:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71
Now, arrange these prime numbers in descending order.
71, 67, 61, 59, 53, 47, 43, 41, 37, 29, 23, 19, 17, 13, 11, 7, 5, 3, 2
Now, 8th position from left end of the row is
71, 67, 61, 59, 53, 47, 43, 41, 37, 29, 23, 19, 17, 13, 11, 7, 5, 3, 2
Hence, 41 is at 8th position from left end of the row is.
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If first 20 prime numbers are arranged in descending order then the number which occurs in 8th position from left end of the row is 37
Solution:
A prime number is a whole number greater than 1 whose only factors are 1 and itself.
The first 20 prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67 and 71.
Arranging the first 20 prime numbers in descending order we get,
Descending order means greatest number to smallest number
67, 61, 59, 53, 47, 43, 41, 37, 31, 29, 23, 19, 17, 13, 11, 7, 5, 3, 2
Now look at the series from left end and find the number in 8th position
Thus the number which occurs in the 8th position from the left end of the row is 37.
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