if first and last term of an AP are 17 and 350 respectively. if the common difference is 9, how many terms are there and what is their sum
Answers
Answered by
8
Heya !!
First term ( A ) = 17
And,
Common difference ( D ) = 9
Last term ( Tn ) = 350
A + ( N - 1 ) × D = 350
17 + ( N - 1 ) × 9 = 350
17 + 9N - 9 = 350
9N + 8 = 350
9N = 350-8
N = 38
Number of terms = 38.
Sn = N/2 × [ 2A + ( N - 1 ) × D ]
S38 = 38/2 × [ 2 × 17 + ( 38 - 1 ) × 9 ]
=> 19 ( 34 + 333 )
=> 19 × 367
=> 6973.
First term ( A ) = 17
And,
Common difference ( D ) = 9
Last term ( Tn ) = 350
A + ( N - 1 ) × D = 350
17 + ( N - 1 ) × 9 = 350
17 + 9N - 9 = 350
9N + 8 = 350
9N = 350-8
N = 38
Number of terms = 38.
Sn = N/2 × [ 2A + ( N - 1 ) × D ]
S38 = 38/2 × [ 2 × 17 + ( 38 - 1 ) × 9 ]
=> 19 ( 34 + 333 )
=> 19 × 367
=> 6973.
Answered by
1
Hey!!
_________________
First term ( A ) = 17
Common Difference ( D ) = 9
Last term = 350
A + ( N - 1 ) × D = 350
=> 17 + ( N - 1 ) × 9 = 350
=> 17 + 9N - 9 = 350
=> 8 + 9N = 350
=> 9N = 350 - 8
=> 9N = 342
=> N = 342 / 9
=> N = 38
Number of terms = 38
Sn = N / 2 [ 2A + ( N - 1 ) × D ]
S38 = 38 / 2 [ 2 ( 17 ) + ( 38 - 1 ) × 9 ]
=> 34 [ 34 + 333 ]
=> 34 × 367
=> 12478 >>>>> Answer
______________________
Hope it will helps you ✌
_________________
First term ( A ) = 17
Common Difference ( D ) = 9
Last term = 350
A + ( N - 1 ) × D = 350
=> 17 + ( N - 1 ) × 9 = 350
=> 17 + 9N - 9 = 350
=> 8 + 9N = 350
=> 9N = 350 - 8
=> 9N = 342
=> N = 342 / 9
=> N = 38
Number of terms = 38
Sn = N / 2 [ 2A + ( N - 1 ) × D ]
S38 = 38 / 2 [ 2 ( 17 ) + ( 38 - 1 ) × 9 ]
=> 34 [ 34 + 333 ]
=> 34 × 367
=> 12478 >>>>> Answer
______________________
Hope it will helps you ✌
Similar questions