If first and last term of an ap is 4 and 81 and common differesnce is 7. Then find no. Of terms and sum of that ap
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Answer:n = 12
S12 = 510
Step-by-step explanation:
a = 4
d = 7
l = 81
a + (n-1) d = 81
4 + (n-1) 7 = 81
4 + 7n -7 = 81
7n = 84
n = 12
S12 = n/2 ( a + l )
=12/2 (4 + 81)
=6 X 85
=510
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