Question

If first and last terms of an AP are 2 and 26. If sum of its terms is 126. Then number of terms will be-

Answer 1

Sn = n/2 [a+l] {a = 1st term & l = last term}

Sn = 126, a = 2, An = 26

126 = n/2 [2+26]

126 = n/2 × 28

126 = 14n

126/14 = n

n = 9

Hence, there are 9 terms in this AP.

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Answer 2

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