Question

If first excitation enrgy for h- like atom is 24ev . then what is its binding energy of third excitation enrgy

Answer 1

The energy of electron of H-like atom in n=n state is given by

E(n)=-13.6Z^2/n^2, where Z is nuclear charge. Energy is in eV.

n=1 gives ground state energy E(1)=-13.6Z^2 eV……………(1)

n=2 gives the energy of first excited state . E(2)=-13.6Z^2/4eV……….(2)

The first excitation energy is given by E(2)-E(1)=13.6Z^2(-1/4+1)=13.6Z^2X(3/4)=24 eV given.

Then, Z^2=(24)(4/3)/13.6=32/13.6.

Therefore ,binding energy =13.6(32/13.6)=32eV

This much energy is to be given to electron in the ground state to liberate it from the atom.

Answer 2

The vitality of electron of H-like molecule in n=n state is given by E(n)=-13.6Z^2/n^2, where Z is atomic charge.

Vitality is in eV. n=1 gives ground state vitality E(1)=-13.6Z^2 eV… …

(1) n=2 gives the vitality of first energized state . E(2)=-13.6Z^2/4eV… … .(2)

The main excitation vitality is given by E(2)- E(1)=13.6Z^2(- 1/4+1)=13.6Z^2X(3/4)=24 eV given.

At that point, Z^2=(24)(4/3)/13.6=32/13.6. Along these lines, restricting vitality =13.6(32/13.6)=32eV

This much vitality is to be given to electron in the ground state to free it from the iota.