if first is ap -4 common difference is 2 find 10 term sum by bijus
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a1= -4
d=2
n=10
Sn=n/2(2a+(n-1)d)
10/2(2(-4)+(10-1)2
=5(-8+18)
=5×10=50
Sn=50
d=2
n=10
Sn=n/2(2a+(n-1)d)
10/2(2(-4)+(10-1)2
=5(-8+18)
=5×10=50
Sn=50
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